-16x^2+192x-560=0

Solution for -16x^2+192x-560=0 equation:

-16x^2+192x-560=0

a = -16; b = 192; c = -560;
Δ = b2-4ac
Δ = 1922-4·(-16)·(-560)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(192)-32}{2*-16}=\frac{-224}{-32}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(192)+32}{2*-16}=\frac{-160}{-32}
=+5
$